[LowellFeierabend]

I have some problems with array.

So first of all,
This program should end, when you write “end” , otherwise should keep all words, and when it ends, Ask for type of formatting (Part with format i know).

I can’t get to work this first part, with keeping words. When i write “end” it will terminate properly, but when i write something else, i’ve got error ;x
Any tips, what i should fix ? or i should use another argument in while ?

Exception in thread "main" java.lang.NullPointerException
   at lab13zad3.main(lab13zad3.java:16)

import java.util.Scanner;
public class lab13zad3{
    public static void main(String[] args) {
       Scanner sc= new Scanner(System.in);
       
       String word;
       String words[]=new String[100];
       int i=0;
       
       String k="end";
       System.out.println("Write some words: ");
       word=sc.next();
       while(word.compareToIgnoreCase(k)!=0){
       i=i+1;
       word=words[i];
       }

[CWC]

I’ve done some modifications and here is the code

import java.util.Scanner;
public class lab13zad3{
    public static void main(String[] args) {
       Scanner sc= new Scanner(System.in);
       String word;
       String words[]=new String[100];
       int i=0;
       
       String k="end";
       System.out.println("Write some words: ");
       word=sc.next();
       while(word.compareToIgnoreCase(k)!=0)
       {
         words[i] = word;
         i=i+1;
         word=sc.next();
       }
       
       
      for(int j=0;j
However there is a small caveat to the above code. When printing, it prints all the values in the array including empty or null strings.
    

[SapnaVishwas]

It stuck again.

if(type.equals("A")){
       int lenght=words.length;
       lenght=i+1;
       i=0;
       while(i
Code is working, but not that way i want.
It's shows properly words:
Cat

Cats

blabla

null (i guess it's that word "end" right, ) Any tips how to replace that with "end" ?

Or somehow i need to assign that "end" to end of array ?
And the second question.
How should code look if i want to have words like that:
c a t s d o g s etc. Smile (Here i have only one thought, that i need somehow add space between words ;x)
Null is because of that "string k = "end" ;d maybe...
    

[CWC]

Question 1:
Difficult without knowing what “i” is in lenght = i + 1; I don’t really know why you even do this step as it makes the first step redundant (int lenght=words.length)
If I understand correctly you want to do what varuint suggests and loop while words[i].compareToIgnoreCase(“end”) != 0, this should avoid the null…

Question 2:
You could use toCharArray on words[i] then loop to print it with spaces between individual characters…

[Abhey]

To eliminate the nulls you can count the number of objects that aren’t null, assign that to a new String array and copy the Strings into the new array. You could also use an ArrayList object instead of a String array, with which you don’t need to specify a size in advance.

You could also do a null/blank check before printing out the words:

if (words[i]!=null && !words[i].empty()){
...
}

[SapnaVishwas]

There is no method named empty() for a String object.

Here is the code that prints all the received words also ignoring nulls now.

import java.util.Scanner;
public class lab13zad3{
    public static void main(String[] args) {
       Scanner sc= new Scanner(System.in);
       
       String word;
       String words[]=new String[100];
       int i=0;
       
       String k="end";
       System.out.println("Write some words: ");
       word=sc.next();
       
       //Add words to the array
       while(word.compareToIgnoreCase(k)!=0)
       {
         words[i] = word;
         i=i+1;
         word=sc.next();
       }
       
       //Add "end" after receiving all the words
      words[i] = k;
      System.out.println("The received words are:");
      for(int j=0;j 0)
           System.out.println(words[j]);
      }
    }
}           

For the second part of the question, are you trying to print all the words without any spaces or printing all words in the same line with a space between each?

[Amit]

Finally get it, before your reply Smile. But i made few fixes and it’s working like a charm.

// This IF format text like that
cat
cat
cat
cat
//
if(typ.equals("B")){
       int length=i+1;
       
       
       for(int x=0;x
And final question !
If want to format text like that (spaced) in the same line.

I.E. c a t d o g c a t etc.
And first thought is, chaAt, for loop and add space between letters ? Am i thinking right ? Smile
Somehow i managed to do that:
if(typ.equals("A")){
           int length=words.length();
           
           for(int z=0;z
    

[Adelaid]

Here is my code in the format you’re looking for

import java.util.Scanner;

public class lab13zad3{
    public static void main(String[] args) {
       Scanner sc= new Scanner(System.in);
       
       String word;
       String words[]=new String[100];
       int i=0;
       
       String k="end";
       System.out.println("Write some words: ");
       word=sc.next();
       
       //Add words to the array
       while(word.compareToIgnoreCase(k)!=0)
       {
         words[i] = word;
         i=i+1;
         word=sc.next();
       }
       
       //Add "end" after receiving all the words
      words[i] = k;
      System.out.println("The received words are:");
      for(int j=0;j 0)
           System.out.println(words[j]);
      }
     
      System.out.println("Word with a space between each character");
      for(String w:words)
      {
        if(w != null && w.length() > 0)
        {
          char temp[] = w.toCharArray();
          for(int c=0;c