Runge-Kutta Method MATLAB Program

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Runge-Kutta method is a popular iteration method of approximating solution of ordinary differential equations. Developed around 1900 by German mathematicians C.Runge and M. W. Kutta, this method is applicable to both families of explicit and implicit functions.

Also known as RK method, the Runge-Kutta method is based on solution procedure of initial value problem in which the initial conditions are known. Based on the order of differential equation, there are different Runge-Kutta methods which are commonly referred to as: RK2, RK3, and RK4 methods.

In earlier tutorial, we’ve already discussed a C program for RK4 method. This tutorial focuses on writing a general program code for Runge-Kutta method in MATLAB along with its mathematical derivation and a numerical example.

Derivation of Runge-Kutta Method:

Let’s consider an initial value problem given as:

y’ = f( t, y),        y(t0) = y0

where,

  • y is an unknown function of time t, which may be scalar or vector quantity
  • y’ is the rate of change of y with respect to t
  • t0 is the initial value of t
  • y0 is the value of y at time t0

Let ‘h’ be the step size such that h > 0. Now, the generation term of the series can be defined as:

yn+1 = yn + h/6 * ( k1 + 2k2 + 2k3 + k4)
tn+1 = tn  + h

for n = 1, 2 , 3, 4, …. such that:

  • k1 = f( tn, yn)
  • k2 = f( tn + h/2 , yn + h/2 k1 )
  • k3 = f( tn + h/2, yn + h/2k2)
  • k4 = f( tn + h, yn + hk3)
  • yn+1 is the Runge-Kutta method approximation of y(tn+1)
  • k1 is the increment which depends on the gradient of starting interval as in Euler’s method
  • k2 is the increment which relies on the slope at the midpoint of the interval, k2 = y+ h/2 * k1
  • k3 is also an increment based on the gradient at midpoint, k3=y+h/2*k2
  • k4 is again an increment whose value depends on end of the end of interval k4 = y + hk3

Runge-Kutta Method in MATLAB:

The given code for Runge-Kutta method in Matlab is applicable to find out the approximate solution of ordinary differential equation of any order. In the source code, the argument ‘df’ is defined to represent equation, making right hand side zero.

The differential equation to be solved is given as input to the program through a MATLAB file. For example, if y ‘ = sin(x) + 2 is to be solved by using this MATLAB source code, following piece of codes should be saved  as ex.m file and opened while executing the above program:

As the Runge-Kutta Methods are based on initial value problem, it is necessary to define the initial condition in any problem. When the program is executed, it asks for initial condition i.e. initial value of x, initial value of y, and the degree of accuracy or error tolerance.

After inputting all the values, the program asks to choose the order of Runge-Kutta method. Based on the order, the calculations are proceeded as explained above in the mathematical derivation. Here’s a sample output of the program:

Runge Kutta method in MATLAB - Select Order
Select the Order of Ordinary Differential Equation

The last part of the code is for displaying graph as shown below:

Runge-Kutta method in MATLAB Graph
Graphical Output using RK4 Method

Runge-Kutta Numerical Example:

Let’s analyze and solve an initial value problem using Runge-Kutta method. We have to approximate y(1.5) and y(1.0) using RK4 method in this problem:

y'(t) = 1 – t*y(t) ; y(0.5) = 2.5

Here, given initial condition: t0 = 0.5, y0 = 2.5

For y’ = 1 – ty, adopt a step size, h = 1. Then, finding the value of k1, k2, k3 and k4 using the formulas discussed in the derivation.

K1 = f(0.5, 2.5) = -0.25
K2 = f(1, 2.375) = -1.375
K3 = f(1, 1.8125) = -0.8125
K4 = f(0.5, 1.6875) = -0.153125
(K1 + 2K2 + 2K3 + K4)/6 = -1.026041667

The first approximation of y, y1 = y0 + h(-1.026041667) = 1.473958333

Next, to approximate y2, we have: t0 = 0.5, y0 = 2.5, and h = 0.5

K1 = f(0.5, 2.5) = -0.25
K2 = f(1, 2.4375) = -0.828125
K3 = f(1, 2.29296875) = -0.719726562
K4 = f(0.5, 2.140136719) = -1.140136719
(K1 + 2K2 + 2K3 + K4)/6 = -0.7476399739

The second approximation of y, y2 = y0 + h(-0.7476399739) = 2.126180013 …. and so on for others.

The whole calculation procedure of this numerical example (and of any program code of Runge-Kutta method in MATLAB) is shown in the table below:

Runge Kutta method in MATLAB - Iteration

In Runge-Kutta method, the accuracy of the result depends on the value of step size, h. Smaller the value of h, higher will be the accuracy of the result obtained. The aforementioned table shows the various value of h in descending order and respective result of the function.

So, whether you’re solving a program manually or by programming (using MATLAB, C, or any other language syntax), the smaller the value of h, smaller will be the error in calculation of result. You can find more Numerical methods tutorial using MATLAB here.

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